2c^2+c=10

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Solution for 2c^2+c=10 equation:


Simplifying
2c2 + c = 10

Reorder the terms:
c + 2c2 = 10

Solving
c + 2c2 = 10

Solving for variable 'c'.

Reorder the terms:
-10 + c + 2c2 = 10 + -10

Combine like terms: 10 + -10 = 0
-10 + c + 2c2 = 0

Factor a trinomial.
(-5 + -2c)(2 + -1c) = 0

Subproblem 1

Set the factor '(-5 + -2c)' equal to zero and attempt to solve: Simplifying -5 + -2c = 0 Solving -5 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -2c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -2c = 0 + 5 -2c = 0 + 5 Combine like terms: 0 + 5 = 5 -2c = 5 Divide each side by '-2'. c = -2.5 Simplifying c = -2.5

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {-2.5, 2}

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